2(4m-5)-(6m+11)=33

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Solution for 2(4m-5)-(6m+11)=33 equation: 



2(4m-5)-(6m+11)=33

We move all terms to the left:

2(4m-5)-(6m+11)-(33)=0

We multiply parentheses

8m-(6m+11)-10-33=0

We get rid of parentheses

8m-6m-11-10-33=0

We add all the numbers together, and all the variables

2m-54=0

We move all terms containing m to the left, all other terms to the right

2m=54

m=54/2

m=27

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