2(4m-5)-(6m+11)=33

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Solution for 2(4m-5)-(6m+11)=33 equation:



2(4m-5)-(6m+11)=33
We move all terms to the left:
2(4m-5)-(6m+11)-(33)=0
We multiply parentheses
8m-(6m+11)-10-33=0
We get rid of parentheses
8m-6m-11-10-33=0
We add all the numbers together, and all the variables
2m-54=0
We move all terms containing m to the left, all other terms to the right
2m=54
m=54/2
m=27

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