2(4m-5)-2(6m+11)=33

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Solution for 2(4m-5)-2(6m+11)=33 equation:



2(4m-5)-2(6m+11)=33
We move all terms to the left:
2(4m-5)-2(6m+11)-(33)=0
We multiply parentheses
8m-12m-10-22-33=0
We add all the numbers together, and all the variables
-4m-65=0
We move all terms containing m to the left, all other terms to the right
-4m=65
m=65/-4
m=-16+1/4

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