2(4m-5)-6m+11)=33

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Solution for 2(4m-5)-6m+11)=33 equation: 



2(4m-5)-6m+11)=33

We move all terms to the left:

2(4m-5)-6m+11)-(33)=0

We add all the numbers together, and all the variables

-6m+2(4m-5)=0

We multiply parentheses

-6m+8m-10=0

We add all the numbers together, and all the variables

2m-10=0

We move all terms containing m to the left, all other terms to the right

2m=10

m=10/2

m=5

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