2(4m-6)=20

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Solution for 2(4m-6)=20 equation: 



2(4m-6)=20

We move all terms to the left:

2(4m-6)-(20)=0

We multiply parentheses

8m-12-20=0

We add all the numbers together, and all the variables

8m-32=0

We move all terms containing m to the left, all other terms to the right

8m=32

m=32/8

m=4

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