2(4n-1)/3=9(n+1)/4

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Solution for 2(4n-1)/3=9(n+1)/4 equation: 



2(4n-1)/3=9(n+1)/4

We move all terms to the left:

2(4n-1)/3-(9(n+1)/4)=0

We calculate fractions


8n/()+(-(9(n+1)*3)/()=0



We calculate terms in parentheses: +(-(9(n+1)*3)/(), so:

-(9(n+1)*3)/(

We multiply all the terms by the denominator


-(9(n+1)*3)



We calculate terms in parentheses: -(9(n+1)*3), so:

9(n+1)*3

We multiply parentheses

27n+27

Back to the equation:

-(27n+27)



We get rid of parentheses

-27n-27

Back to the equation:

+(-27n-27)



We get rid of parentheses

8n/()-27n-27=0

We multiply all the terms by the denominator


8n-27n*()-27*()=0

We add all the numbers together, and all the variables

8n-27n*()=0

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