2(4n-3)=9(n+2)+3n

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Solution for 2(4n-3)=9(n+2)+3n equation: 



2(4n-3)=9(n+2)+3n

We move all terms to the left:

2(4n-3)-(9(n+2)+3n)=0

We multiply parentheses

8n-(9(n+2)+3n)-6=0



We calculate terms in parentheses: -(9(n+2)+3n), so:

9(n+2)+3n

We add all the numbers together, and all the variables

3n+9(n+2)

We multiply parentheses

3n+9n+18

We add all the numbers together, and all the variables

12n+18

Back to the equation:

-(12n+18)



We get rid of parentheses

8n-12n-18-6=0

We add all the numbers together, and all the variables

-4n-24=0

We move all terms containing n to the left, all other terms to the right

-4n=24

n=24/-4

n=-6

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