2(4q+3)=2(2q-7)

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Solution for 2(4q+3)=2(2q-7) equation:



2(4q+3)=2(2q-7)
We move all terms to the left:
2(4q+3)-(2(2q-7))=0
We multiply parentheses
8q-(2(2q-7))+6=0
We calculate terms in parentheses: -(2(2q-7)), so:
2(2q-7)
We multiply parentheses
4q-14
Back to the equation:
-(4q-14)
We get rid of parentheses
8q-4q+14+6=0
We add all the numbers together, and all the variables
4q+20=0
We move all terms containing q to the left, all other terms to the right
4q=-20
q=-20/4
q=-5

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