2(4r+2)=4r-12(r-1)

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Solution for 2(4r+2)=4r-12(r-1) equation: 



2(4r+2)=4r-12(r-1)

We move all terms to the left:

2(4r+2)-(4r-12(r-1))=0

We multiply parentheses

8r-(4r-12(r-1))+4=0



We calculate terms in parentheses: -(4r-12(r-1)), so:

4r-12(r-1)

We multiply parentheses

4r-12r+12

We add all the numbers together, and all the variables

-8r+12

Back to the equation:

-(-8r+12)



We get rid of parentheses

8r+8r-12+4=0

We add all the numbers together, and all the variables

16r-8=0

We move all terms containing r to the left, all other terms to the right

16r=8

r=8/16

r=1/2

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