2(4r+6)=2/3(12r=18)

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Solution for 2(4r+6)=2/3(12r=18) equation: 



2(4r+6)=2/3(12r=18)

We move all terms to the left:

2(4r+6)-(2/3(12r)=0



Domain of the equation: 312r!=0

r!=0/312

r!=0

r∈R



We multiply parentheses

8r-(2/312r+12=0

We multiply all the terms by the denominator


8r*312r+12-(2=0

We add all the numbers together, and all the variables

8r*312r=0

Wy multiply elements

2496r^2=0

a = 2496; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2496·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$r=\frac{-b}{2a}=\frac{0}{4992}=0$

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