2(4s+5)-4s=2(2s+1)-5

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Solution for 2(4s+5)-4s=2(2s+1)-5 equation: 


Simplifying
2(4s + 5) + -4s = 2(2s + 1) + -5

Reorder the terms:
2(5 + 4s) + -4s = 2(2s + 1) + -5
(5 * 2 + 4s * 2) + -4s = 2(2s + 1) + -5
(10 + 8s) + -4s = 2(2s + 1) + -5

Combine like terms: 8s + -4s = 4s
10 + 4s = 2(2s + 1) + -5

Reorder the terms:
10 + 4s = 2(1 + 2s) + -5
10 + 4s = (1 * 2 + 2s * 2) + -5
10 + 4s = (2 + 4s) + -5

Reorder the terms:
10 + 4s = 2 + -5 + 4s

Combine like terms: 2 + -5 = -3
10 + 4s = -3 + 4s

Add '-4s' to each side of the equation.
10 + 4s + -4s = -3 + 4s + -4s

Combine like terms: 4s + -4s = 0
10 + 0 = -3 + 4s + -4s
10 = -3 + 4s + -4s

Combine like terms: 4s + -4s = 0
10 = -3 + 0
10 = -3

Solving
10 = -3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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