2(4t+1)-5=t-(t+2)

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Solution for 2(4t+1)-5=t-(t+2) equation:



2(4t+1)-5=t-(t+2)
We move all terms to the left:
2(4t+1)-5-(t-(t+2))=0
We multiply parentheses
8t-(t-(t+2))+2-5=0
We calculate terms in parentheses: -(t-(t+2)), so:
t-(t+2)
We get rid of parentheses
t-t-2
We add all the numbers together, and all the variables
-2
Back to the equation:
-(-2)
We add all the numbers together, and all the variables
8t-1=0
We move all terms containing t to the left, all other terms to the right
8t=1
t=1/8
t=1/8

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