2(4t-6)=10t+7

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Solution for 2(4t-6)=10t+7 equation: 



2(4t-6)=10t+7

We move all terms to the left:

2(4t-6)-(10t+7)=0

We multiply parentheses

8t-(10t+7)-12=0

We get rid of parentheses

8t-10t-7-12=0

We add all the numbers together, and all the variables

-2t-19=0

We move all terms containing t to the left, all other terms to the right

-2t=19

t=19/-2

t=-9+1/2

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