2(4t-6)=21t+7

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Solution for 2(4t-6)=21t+7 equation: 



2(4t-6)=21t+7

We move all terms to the left:

2(4t-6)-(21t+7)=0

We multiply parentheses

8t-(21t+7)-12=0

We get rid of parentheses

8t-21t-7-12=0

We add all the numbers together, and all the variables

-13t-19=0

We move all terms containing t to the left, all other terms to the right

-13t=19

t=19/-13

t=-1+6/13

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