2(4u+2)=12(u-6)

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Solution for 2(4u+2)=12(u-6) equation: 



2(4u+2)=12(u-6)

We move all terms to the left:

2(4u+2)-(12(u-6))=0

We multiply parentheses

8u-(12(u-6))+4=0



We calculate terms in parentheses: -(12(u-6)), so:

12(u-6)

We multiply parentheses

12u-72

Back to the equation:

-(12u-72)



We get rid of parentheses

8u-12u+72+4=0

We add all the numbers together, and all the variables

-4u+76=0

We move all terms containing u to the left, all other terms to the right

-4u=-76

u=-76/-4

u=+19

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