2(4v+1)=2+6v

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Solution for 2(4v+1)=2+6v equation: 



2(4v+1)=2+6v

We move all terms to the left:

2(4v+1)-(2+6v)=0

We add all the numbers together, and all the variables

2(4v+1)-(6v+2)=0

We multiply parentheses

8v-(6v+2)+2=0

We get rid of parentheses

8v-6v-2+2=0

We add all the numbers together, and all the variables

2v=0

v=0/2

v=0

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