2(4w+5-10)+1=-5(2w+1)+6w+8

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Solution for 2(4w+5-10)+1=-5(2w+1)+6w+8 equation: 



2(4w+5-10)+1=-5(2w+1)+6w+8

We move all terms to the left:

2(4w+5-10)+1-(-5(2w+1)+6w+8)=0

We add all the numbers together, and all the variables

2(4w-5)-(-5(2w+1)+6w+8)+1=0

We multiply parentheses

8w-(-5(2w+1)+6w+8)-10+1=0



We calculate terms in parentheses: -(-5(2w+1)+6w+8), so:

-5(2w+1)+6w+8

We add all the numbers together, and all the variables

6w-5(2w+1)+8

We multiply parentheses

6w-10w-5+8

We add all the numbers together, and all the variables

-4w+3

Back to the equation:

-(-4w+3)



We add all the numbers together, and all the variables

8w-(-4w+3)-9=0

We get rid of parentheses

8w+4w-3-9=0

We add all the numbers together, and all the variables

12w-12=0

We move all terms containing w to the left, all other terms to the right

12w=12

w=12/12

w=1

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