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2(4x+1)(x-3)=0
We multiply parentheses ..
2(+4x^2-12x+x-3)=0
We multiply parentheses
8x^2-24x+2x-6=0
We add all the numbers together, and all the variables
8x^2-22x-6=0
a = 8; b = -22; c = -6;
Δ = b2-4ac
Δ = -222-4·8·(-6)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-26}{2*8}=\frac{-4}{16} =-1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+26}{2*8}=\frac{48}{16} =3 $
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