2(4x+1)+5(3x+2)=58

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Solution for 2(4x+1)+5(3x+2)=58 equation:


Simplifying
2(4x + 1) + 5(3x + 2) = 58

Reorder the terms:
2(1 + 4x) + 5(3x + 2) = 58
(1 * 2 + 4x * 2) + 5(3x + 2) = 58
(2 + 8x) + 5(3x + 2) = 58

Reorder the terms:
2 + 8x + 5(2 + 3x) = 58
2 + 8x + (2 * 5 + 3x * 5) = 58
2 + 8x + (10 + 15x) = 58

Reorder the terms:
2 + 10 + 8x + 15x = 58

Combine like terms: 2 + 10 = 12
12 + 8x + 15x = 58

Combine like terms: 8x + 15x = 23x
12 + 23x = 58

Solving
12 + 23x = 58

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + 23x = 58 + -12

Combine like terms: 12 + -12 = 0
0 + 23x = 58 + -12
23x = 58 + -12

Combine like terms: 58 + -12 = 46
23x = 46

Divide each side by '23'.
x = 2

Simplifying
x = 2

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