2(4x+1)+7(8x+2)=12(x+6)-4(x+2)-6

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Solution for 2(4x+1)+7(8x+2)=12(x+6)-4(x+2)-6 equation: 



2(4x+1)+7(8x+2)=12(x+6)-4(x+2)-6

We move all terms to the left:

2(4x+1)+7(8x+2)-(12(x+6)-4(x+2)-6)=0

We multiply parentheses

8x+56x-(12(x+6)-4(x+2)-6)+2+14=0



We calculate terms in parentheses: -(12(x+6)-4(x+2)-6), so:

12(x+6)-4(x+2)-6

We multiply parentheses

12x-4x+72-8-6

We add all the numbers together, and all the variables

8x+58

Back to the equation:

-(8x+58)



We add all the numbers together, and all the variables

64x-(8x+58)+16=0

We get rid of parentheses

64x-8x-58+16=0

We add all the numbers together, and all the variables

56x-42=0

We move all terms containing x to the left, all other terms to the right

56x=42

x=42/56

x=3/4

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