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2(4x+1)-3=()x+()
We move all terms to the left:
2(4x+1)-3-(()x+())=0
We multiply parentheses
8x-(()x+())+2-3=0
We calculate terms in parentheses: -(()x+()), so:We add all the numbers together, and all the variables
()x+()
We add all the numbers together, and all the variables
()x
Back to the equation:
-(()x)
8x-(()x)-1=0
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We calculate terms in parentheses: -(()x), so:We move all terms containing x to the left, all other terms to the right
()x
8x-(()x)=1
| 1−3t+5=7 | | 5a+6a-15=18 | | 92=213-w | | 2^x-3=30 | | 6h+6.2=48.2 | | 4x3=14x-103 | | (2u+2)=(5u-10) | | 14=70/c | | M=32(4)^d | | 270=-x+157 | | 1/5(10-5d)=5d-16 | | -5a=105 | | 20=w(-5/6) | | 5x*5=8 | | 6c+c+5=40 | | 107-y=226 | | 2(3x-4)=8x-8* | | -2t+4t-7=9 | | 8-5x=-(2x+10) | | 49=4x+7(-x+18) | | V=(18-2x)(32-2x)(x) | | x15=150 | | 3x-4.5=7x+8.5 | | (x+8)2=16–x2+9x | | 7(d-2)=5(d=2) | | 8(10-w)=2w | | A/b-5=9 | | 12x+19+22x-8=180 | | w+1=18 | | s-3=65 | | 3(3x+2)=-6(-x+1) | | 6+2(3m-5)=20 |