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2(4x+1)-3=8x+(-1)
We move all terms to the left:
2(4x+1)-3-(8x+(-1))=0
We multiply parentheses
8x-(8x+(-1))+2-3=0
We calculate terms in parentheses: -(8x+(-1)), so:We add all the numbers together, and all the variables
8x+(-1)
We add all the numbers together, and all the variables
8x-1
Back to the equation:
-(8x-1)
8x-(8x-1)-1=0
We get rid of parentheses
8x-8x+1-1=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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