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2(4x+1)-4(5-x)-5=2(10-x)
We move all terms to the left:
2(4x+1)-4(5-x)-5-(2(10-x))=0
We add all the numbers together, and all the variables
2(4x+1)-4(-1x+5)-(2(-1x+10))-5=0
We multiply parentheses
8x+4x-(2(-1x+10))+2-20-5=0
We calculate terms in parentheses: -(2(-1x+10)), so:We add all the numbers together, and all the variables
2(-1x+10)
We multiply parentheses
-2x+20
Back to the equation:
-(-2x+20)
12x-(-2x+20)-23=0
We get rid of parentheses
12x+2x-20-23=0
We add all the numbers together, and all the variables
14x-43=0
We move all terms containing x to the left, all other terms to the right
14x=43
x=43/14
x=3+1/14
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