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2(4x+1)=3(x+3)-2
We move all terms to the left:
2(4x+1)-(3(x+3)-2)=0
We multiply parentheses
8x-(3(x+3)-2)+2=0
We calculate terms in parentheses: -(3(x+3)-2), so:We get rid of parentheses
3(x+3)-2
We multiply parentheses
3x+9-2
We add all the numbers together, and all the variables
3x+7
Back to the equation:
-(3x+7)
8x-3x-7+2=0
We add all the numbers together, and all the variables
5x-5=0
We move all terms containing x to the left, all other terms to the right
5x=5
x=5/5
x=1
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