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2(4x+1)=4(2x-1)
We move all terms to the left:
2(4x+1)-(4(2x-1))=0
We multiply parentheses
8x-(4(2x-1))+2=0
We calculate terms in parentheses: -(4(2x-1)), so:We get rid of parentheses
4(2x-1)
We multiply parentheses
8x-4
Back to the equation:
-(8x-4)
8x-8x+4+2=0
We add all the numbers together, and all the variables
6!=0
There is no solution for this equation
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