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2(4x+1)=4(3x-5)
We move all terms to the left:
2(4x+1)-(4(3x-5))=0
We multiply parentheses
8x-(4(3x-5))+2=0
We calculate terms in parentheses: -(4(3x-5)), so:We get rid of parentheses
4(3x-5)
We multiply parentheses
12x-20
Back to the equation:
-(12x-20)
8x-12x+20+2=0
We add all the numbers together, and all the variables
-4x+22=0
We move all terms containing x to the left, all other terms to the right
-4x=-22
x=-22/-4
x=5+1/2
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