2(4x+2)+2(3x-1)=58

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Solution for 2(4x+2)+2(3x-1)=58 equation: 



2(4x+2)+2(3x-1)=58

We move all terms to the left:

2(4x+2)+2(3x-1)-(58)=0

We multiply parentheses

8x+6x+4-2-58=0

We add all the numbers together, and all the variables

14x-56=0

We move all terms containing x to the left, all other terms to the right

14x=56

x=56/14

x=4

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