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2(4x+3)+2=3x-(2x+4)
We move all terms to the left:
2(4x+3)+2-(3x-(2x+4))=0
We multiply parentheses
8x-(3x-(2x+4))+6+2=0
We calculate terms in parentheses: -(3x-(2x+4)), so:We add all the numbers together, and all the variables
3x-(2x+4)
We get rid of parentheses
3x-2x-4
We add all the numbers together, and all the variables
x-4
Back to the equation:
-(x-4)
8x-(x-4)+8=0
We get rid of parentheses
8x-x+4+8=0
We add all the numbers together, and all the variables
7x+12=0
We move all terms containing x to the left, all other terms to the right
7x=-12
x=-12/7
x=-1+5/7
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