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2(4x+3)+4=3x-3(2x+4)
We move all terms to the left:
2(4x+3)+4-(3x-3(2x+4))=0
We multiply parentheses
8x-(3x-3(2x+4))+6+4=0
We calculate terms in parentheses: -(3x-3(2x+4)), so:We add all the numbers together, and all the variables
3x-3(2x+4)
We multiply parentheses
3x-6x-12
We add all the numbers together, and all the variables
-3x-12
Back to the equation:
-(-3x-12)
8x-(-3x-12)+10=0
We get rid of parentheses
8x+3x+12+10=0
We add all the numbers together, and all the variables
11x+22=0
We move all terms containing x to the left, all other terms to the right
11x=-22
x=-22/11
x=-2
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