2(4x+3)=-4x(5x-4)+5x

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Solution for 2(4x+3)=-4x(5x-4)+5x equation: 



2(4x+3)=-4x(5x-4)+5x

We move all terms to the left:

2(4x+3)-(-4x(5x-4)+5x)=0

We multiply parentheses

8x-(-4x(5x-4)+5x)+6=0



We calculate terms in parentheses: -(-4x(5x-4)+5x), so:

-4x(5x-4)+5x

We add all the numbers together, and all the variables

5x-4x(5x-4)

We multiply parentheses

-20x^2+5x+16x

We add all the numbers together, and all the variables

-20x^2+21x

Back to the equation:

-(-20x^2+21x)



We get rid of parentheses

20x^2-21x+8x+6=0

We add all the numbers together, and all the variables

20x^2-13x+6=0

a = 20; b = -13; c = +6;
Δ = b2-4ac
Δ = -132-4·20·6
Δ = -311
Delta is less than zero, so there is no solution for the equation

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