2(4x+3)=10x-20

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Solution for 2(4x+3)=10x-20 equation: 



2(4x+3)=10x-20

We move all terms to the left:

2(4x+3)-(10x-20)=0

We multiply parentheses

8x-(10x-20)+6=0

We get rid of parentheses

8x-10x+20+6=0

We add all the numbers together, and all the variables

-2x+26=0

We move all terms containing x to the left, all other terms to the right

-2x=-26

x=-26/-2

x=+13

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