2(4x+3)=7-3(x-5)

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Solution for 2(4x+3)=7-3(x-5) equation: 



2(4x+3)=7-3(x-5)

We move all terms to the left:

2(4x+3)-(7-3(x-5))=0

We multiply parentheses

8x-(7-3(x-5))+6=0



We calculate terms in parentheses: -(7-3(x-5)), so:

7-3(x-5)

determiningTheFunctionDomain
-3(x-5)+7

We multiply parentheses

-3x+15+7

We add all the numbers together, and all the variables

-3x+22

Back to the equation:

-(-3x+22)



We get rid of parentheses

8x+3x-22+6=0

We add all the numbers together, and all the variables

11x-16=0

We move all terms containing x to the left, all other terms to the right

11x=16

x=16/11

x=1+5/11

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