2(4x+4)+6=3x+19

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Solution for 2(4x+4)+6=3x+19 equation: 



2(4x+4)+6=3x+19

We move all terms to the left:

2(4x+4)+6-(3x+19)=0

We multiply parentheses

8x-(3x+19)+8+6=0

We get rid of parentheses

8x-3x-19+8+6=0

We add all the numbers together, and all the variables

5x-5=0

We move all terms containing x to the left, all other terms to the right

5x=5

x=5/5

x=1

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