2(4x+4)=4(4x-3)+3x

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Solution for 2(4x+4)=4(4x-3)+3x equation: 



2(4x+4)=4(4x-3)+3x

We move all terms to the left:

2(4x+4)-(4(4x-3)+3x)=0

We multiply parentheses

8x-(4(4x-3)+3x)+8=0



We calculate terms in parentheses: -(4(4x-3)+3x), so:

4(4x-3)+3x

We add all the numbers together, and all the variables

3x+4(4x-3)

We multiply parentheses

3x+16x-12

We add all the numbers together, and all the variables

19x-12

Back to the equation:

-(19x-12)



We get rid of parentheses

8x-19x+12+8=0

We add all the numbers together, and all the variables

-11x+20=0

We move all terms containing x to the left, all other terms to the right

-11x=-20

x=-20/-11

x=1+9/11

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