2(4x+5)=-33+27

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Solution for 2(4x+5)=-33+27 equation: 



2(4x+5)=-33+27

We move all terms to the left:

2(4x+5)-(-33+27)=0

We add all the numbers together, and all the variables

2(4x+5)-(-6)=0

We add all the numbers together, and all the variables

2(4x+5)+6=0

We multiply parentheses

8x+10+6=0

We add all the numbers together, and all the variables

8x+16=0

We move all terms containing x to the left, all other terms to the right

8x=-16

x=-16/8

x=-2

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