2(4x+5)=40+27

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Solution for 2(4x+5)=40+27 equation: 



2(4x+5)=40+27

We move all terms to the left:

2(4x+5)-(40+27)=0

We add all the numbers together, and all the variables

2(4x+5)-67=0

We multiply parentheses

8x+10-67=0

We add all the numbers together, and all the variables

8x-57=0

We move all terms containing x to the left, all other terms to the right

8x=57

x=57/8

x=7+1/8

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