2(4x+8-x2)=9x+7

Solution for 2(4x+8-x2)=9x+7 equation:

2(4x+8-x2)=9x+7

We move all terms to the left:

2(4x+8-x2)-(9x+7)=0

We add all the numbers together, and all the variables

2(+4x-1x^2+8)-(9x+7)=0

We multiply parentheses

-2x^2+8x-(9x+7)+16=0

We get rid of parentheses

-2x^2+8x-9x-7+16=0

We add all the numbers together, and all the variables

-2x^2-1x+9=0

a = -2; b = -1; c = +9;
Δ = b2-4ac
Δ = -12-4·(-2)·9
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{73}}{2*-2}=\frac{1-\sqrt{73}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{73}}{2*-2}=\frac{1+\sqrt{73}}{-4}
$