2(4x-1)+2x=8x+(-2x-2+4)

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Solution for 2(4x-1)+2x=8x+(-2x-2+4) equation: 



2(4x-1)+2x=8x+(-2x-2+4)

We move all terms to the left:

2(4x-1)+2x-(8x+(-2x-2+4))=0

We add all the numbers together, and all the variables

2(4x-1)+2x-(8x+(-2x+2))=0

We add all the numbers together, and all the variables

2x+2(4x-1)-(8x+(-2x+2))=0

We multiply parentheses

2x+8x-(8x+(-2x+2))-2=0



We calculate terms in parentheses: -(8x+(-2x+2)), so:

8x+(-2x+2)

We get rid of parentheses

8x-2x+2

We add all the numbers together, and all the variables

6x+2

Back to the equation:

-(6x+2)



We add all the numbers together, and all the variables

10x-(6x+2)-2=0

We get rid of parentheses

10x-6x-2-2=0

We add all the numbers together, and all the variables

4x-4=0

We move all terms containing x to the left, all other terms to the right

4x=4

x=4/4

x=1

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