2(4x-1)+6x+2=4(x+1)+6

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Solution for 2(4x-1)+6x+2=4(x+1)+6 equation: 



2(4x-1)+6x+2=4(x+1)+6

We move all terms to the left:

2(4x-1)+6x+2-(4(x+1)+6)=0

We add all the numbers together, and all the variables

6x+2(4x-1)-(4(x+1)+6)+2=0

We multiply parentheses

6x+8x-(4(x+1)+6)-2+2=0



We calculate terms in parentheses: -(4(x+1)+6), so:

4(x+1)+6

We multiply parentheses

4x+4+6

We add all the numbers together, and all the variables

4x+10

Back to the equation:

-(4x+10)



We add all the numbers together, and all the variables

14x-(4x+10)=0

We get rid of parentheses

14x-4x-10=0

We add all the numbers together, and all the variables

10x-10=0

We move all terms containing x to the left, all other terms to the right

10x=10

x=10/10

x=1

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