2(4x-1)=10(1x-3)+4

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Solution for 2(4x-1)=10(1x-3)+4 equation: 



2(4x-1)=10(1x-3)+4

We move all terms to the left:

2(4x-1)-(10(1x-3)+4)=0

We add all the numbers together, and all the variables

2(4x-1)-(10(x-3)+4)=0

We multiply parentheses

8x-(10(x-3)+4)-2=0



We calculate terms in parentheses: -(10(x-3)+4), so:

10(x-3)+4

We multiply parentheses

10x-30+4

We add all the numbers together, and all the variables

10x-26

Back to the equation:

-(10x-26)



We get rid of parentheses

8x-10x+26-2=0

We add all the numbers together, and all the variables

-2x+24=0

We move all terms containing x to the left, all other terms to the right

-2x=-24

x=-24/-2

x=+12

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