2(4x-1)=8x2

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Solution for 2(4x-1)=8x2 equation: 



2(4x-1)=8x^2

We move all terms to the left:

2(4x-1)-(8x^2)=0

determiningTheFunctionDomain
-8x^2+2(4x-1)=0

We multiply parentheses

-8x^2+8x-2=0

a = -8; b = 8; c = -2;
Δ = b2-4ac
Δ = 82-4·(-8)·(-2)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-8}{-16}=1/2$

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