2(4x-18)+10=-6(3x-4)

Solution for 2(4x-18)+10=-6(3x-4) equation:

2(4x-18)+10=-6(3x-4)

We move all terms to the left:

2(4x-18)+10-(-6(3x-4))=0

We multiply parentheses

8x-(-6(3x-4))-36+10=0


We calculate terms in parentheses: -(-6(3x-4)), so:

-6(3x-4)

We multiply parentheses

-18x+24

Back to the equation:

-(-18x+24)


We add all the numbers together, and all the variables

8x-(-18x+24)-26=0

We get rid of parentheses

8x+18x-24-26=0

We add all the numbers together, and all the variables

26x-50=0

We move all terms containing x to the left, all other terms to the right

26x=50

x=50/26

x=1+12/13