2(4x-2)+7(-3+5)=(32+44x)

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Solution for 2(4x-2)+7(-3+5)=(32+44x) equation: 



2(4x-2)+7(-3+5)=(32+44x)

We move all terms to the left:

2(4x-2)+7(-3+5)-((32+44x))=0

We add all the numbers together, and all the variables

2(4x-2)-((44x+32))+72=0

We multiply parentheses

8x-((44x+32))-4+72=0



We calculate terms in parentheses: -((44x+32)), so:

(44x+32)

We get rid of parentheses

44x+32

Back to the equation:

-(44x+32)



We add all the numbers together, and all the variables

8x-(44x+32)+68=0

We get rid of parentheses

8x-44x-32+68=0

We add all the numbers together, and all the variables

-36x+36=0

We move all terms containing x to the left, all other terms to the right

-36x=-36

x=-36/-36

x=1

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