2(4x-3)-8(x+1)=4x+2

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Solution for 2(4x-3)-8(x+1)=4x+2 equation: 



2(4x-3)-8(x+1)=4x+2

We move all terms to the left:

2(4x-3)-8(x+1)-(4x+2)=0

We multiply parentheses

8x-8x-(4x+2)-6-8=0

We get rid of parentheses

8x-8x-4x-2-6-8=0

We add all the numbers together, and all the variables

-4x-16=0

We move all terms containing x to the left, all other terms to the right

-4x=16

x=16/-4

x=-4

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