2(4x-3)-8=(-7-x)=36

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Solution for 2(4x-3)-8=(-7-x)=36 equation: 



2(4x-3)-8=(-7-x)=36

We move all terms to the left:

2(4x-3)-8-((-7-x))=0

We add all the numbers together, and all the variables

2(4x-3)-((-1x-7))-8=0

We multiply parentheses

8x-((-1x-7))-6-8=0



We calculate terms in parentheses: -((-1x-7)), so:

(-1x-7)

We get rid of parentheses

-1x-7

Back to the equation:

-(-1x-7)



We add all the numbers together, and all the variables

8x-(-1x-7)-14=0

We get rid of parentheses

8x+1x+7-14=0

We add all the numbers together, and all the variables

9x-7=0

We move all terms containing x to the left, all other terms to the right

9x=7

x=7/9

x=7/9

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