2(4x-3)-8=2(2x+1)

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Solution for 2(4x-3)-8=2(2x+1) equation: 



2(4x-3)-8=2(2x+1)

We move all terms to the left:

2(4x-3)-8-(2(2x+1))=0

We multiply parentheses

8x-(2(2x+1))-6-8=0



We calculate terms in parentheses: -(2(2x+1)), so:

2(2x+1)

We multiply parentheses

4x+2

Back to the equation:

-(4x+2)



We add all the numbers together, and all the variables

8x-(4x+2)-14=0

We get rid of parentheses

8x-4x-2-14=0

We add all the numbers together, and all the variables

4x-16=0

We move all terms containing x to the left, all other terms to the right

4x=16

x=16/4

x=4

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