2(4x-3)-8=4(1-2x)+10x

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Solution for 2(4x-3)-8=4(1-2x)+10x equation:



2(4x-3)-8=4(1-2x)+10x
We move all terms to the left:
2(4x-3)-8-(4(1-2x)+10x)=0
We add all the numbers together, and all the variables
2(4x-3)-(4(-2x+1)+10x)-8=0
We multiply parentheses
8x-(4(-2x+1)+10x)-6-8=0
We calculate terms in parentheses: -(4(-2x+1)+10x), so:
4(-2x+1)+10x
We add all the numbers together, and all the variables
10x+4(-2x+1)
We multiply parentheses
10x-8x+4
We add all the numbers together, and all the variables
2x+4
Back to the equation:
-(2x+4)
We add all the numbers together, and all the variables
8x-(2x+4)-14=0
We get rid of parentheses
8x-2x-4-14=0
We add all the numbers together, and all the variables
6x-18=0
We move all terms containing x to the left, all other terms to the right
6x=18
x=18/6
x=3

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