2(4x-3)=2(x+2)+8

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Solution for 2(4x-3)=2(x+2)+8 equation: 



2(4x-3)=2(x+2)+8

We move all terms to the left:

2(4x-3)-(2(x+2)+8)=0

We multiply parentheses

8x-(2(x+2)+8)-6=0



We calculate terms in parentheses: -(2(x+2)+8), so:

2(x+2)+8

We multiply parentheses

2x+4+8

We add all the numbers together, and all the variables

2x+12

Back to the equation:

-(2x+12)



We get rid of parentheses

8x-2x-12-6=0

We add all the numbers together, and all the variables

6x-18=0

We move all terms containing x to the left, all other terms to the right

6x=18

x=18/6

x=3

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