2(4x-3)=7(x+4)

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Solution for 2(4x-3)=7(x+4) equation:



2(4x-3)=7(x+4)
We move all terms to the left:
2(4x-3)-(7(x+4))=0
We multiply parentheses
8x-(7(x+4))-6=0
We calculate terms in parentheses: -(7(x+4)), so:
7(x+4)
We multiply parentheses
7x+28
Back to the equation:
-(7x+28)
We get rid of parentheses
8x-7x-28-6=0
We add all the numbers together, and all the variables
x-34=0
We move all terms containing x to the left, all other terms to the right
x=34

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