2(4x-3)=7(x+4)

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Solution for 2(4x-3)=7(x+4) equation: 



2(4x-3)=7(x+4)

We move all terms to the left:

2(4x-3)-(7(x+4))=0

We multiply parentheses

8x-(7(x+4))-6=0



We calculate terms in parentheses: -(7(x+4)), so:

7(x+4)

We multiply parentheses

7x+28

Back to the equation:

-(7x+28)



We get rid of parentheses

8x-7x-28-6=0

We add all the numbers together, and all the variables

x-34=0

We move all terms containing x to the left, all other terms to the right

x=34

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