2(4x-4)-4(3x+5)-16x=0

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Solution for 2(4x-4)-4(3x+5)-16x=0 equation: 



2(4x-4)-4(3x+5)-16x=0

We add all the numbers together, and all the variables

-16x+2(4x-4)-4(3x+5)=0

We multiply parentheses

-16x+8x-12x-8-20=0

We add all the numbers together, and all the variables

-20x-28=0

We move all terms containing x to the left, all other terms to the right

-20x=28

x=28/-20

x=-1+2/5

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