2(4x-4)=4x+32

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Solution for 2(4x-4)=4x+32 equation: 



2(4x-4)=4x+32

We move all terms to the left:

2(4x-4)-(4x+32)=0

We multiply parentheses

8x-(4x+32)-8=0

We get rid of parentheses

8x-4x-32-8=0

We add all the numbers together, and all the variables

4x-40=0

We move all terms containing x to the left, all other terms to the right

4x=40

x=40/4

x=10

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